
根据∫(a→b) ƒ(x) dx = f(b) - f(a), f(x) = ∫ ƒ(x) dx追问

sin^xcos2xdx求不定积分

2 解(一) 令 u cos x , xdx dx dv 2 2 2 x x x cos xdx 2

三角换元公式类.1 tan^2=sec^2sec^2-1=tan^21-sin^2=cos^22.

求不定积分 ∫((1 sin^2x)/(1 cos2x))dx
根据∫(a→b) ƒ(x) dx = f(b) - f(a), f(x) = ∫ ƒ(x) dx追问
sin^xcos2xdx求不定积分
2 解(一) 令 u cos x , xdx dx dv 2 2 2 x x x cos xdx 2
三角换元公式类.1 tan^2=sec^2sec^2-1=tan^21-sin^2=cos^22.
求不定积分 ∫((1 sin^2x)/(1 cos2x))dx