
(cos^4x-cos^6x )dx=?
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定积分cos^6sin^2 dx上限是π/2 下限是0
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sin^2 x该怎样化简?
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tωcos(∞ ∞−∫=tdtωje∞ ∞−∫)ω(δπ2=tdtωje

∫ x*cscx^2*cotx^2 dx 怎么做啊? 急求
(cos^4x-cos^6x )dx=?
定积分cos^6sin^2 dx上限是π/2 下限是0
sin^2 x该怎样化简?
tωcos(∞ ∞−∫=tdtωje∞ ∞−∫)ω(δπ2=tdtωje
∫ x*cscx^2*cotx^2 dx 怎么做啊? 急求