![cos2α,sin2α,tan2α,cos∧2α,sin∧2α,tan∧2α你们知道分别为 cos2α-1](https://img.wumaow.org/upload/tu2/17870148.jpg)
cos2α,sin2α,tan2α,cos∧2α,sin∧2α,tan∧2α你们知道分别为
![若锐角θ满足sinθ cosθ,且sinθ cosθ=√6/2,那么tan(θ-π/6)的值 cos2α-1](https://img.wumaow.org/upload/tu2/17870149.jpg)
若锐角θ满足sinθ cosθ,且sinθ cosθ=√6/2,那么tan(θ-π/6)的值
![根号(cos∧2 600度)是多少?怎么算 cos2α-1](https://img.wumaow.org/upload/tu2/17870150.jpg)
根号(cos∧2 600度)是多少?怎么算
![α=kπ 7π/12或a=kπ-π/12,∵sⅰna-cosa>1,∴a在第二象限即a=2kπ cos2α-1](https://img.wumaow.org/upload/tu2/17870151.jpg)
α=kπ 7π/12或a=kπ-π/12,∵sⅰna-cosa>1,∴a在第二象限即a=2kπ
图片内容是:cos2α-1
![((sinα)/(sinα-cosα))-(sinα cosα)/(tanα-1))化简 cos2α-1](https://img.wumaow.org/upload/tu2/17870152.jpg)
((sinα)/(sinα-cosα))-(sinα cosα)/(tanα-1))化简
![已知tanα=-1/3计算1/2sinαcosα cos2α-1](https://img.wumaow.org/upload/tu2/17870153.jpg)
已知tanα=-1/3计算1/2sinαcosα
![sinacosa可以得到根号3sinx/2cosx/2=根号3/2sinx根据二倍角公式cosα cos2α-1](https://img.wumaow.org/upload/tu2/17870154.jpg)
sinacosa可以得到根号3sinx/2cosx/2=根号3/2sinx根据二倍角公式cosα
![2sinαcosα=3/4 ① (sinα)^2 (cosα)^2=1 ② 由① ②,得 (sinα cos2α-1](https://img.wumaow.org/upload/tu2/17870155.jpg)
2sinαcosα=3/4 ① (sinα)^2 (cosα)^2=1 ② 由① ②,得 (sinα
![化简√2cosα-√2sinα 2 2011-10-17 (2-2cosθ)/(3-2sinθ) 求化简 cos2α-1](https://img.wumaow.org/upload/tu2/17870156.jpg)
化简√2cosα-√2sinα 2 2011-10-17 (2-2cosθ)/(3-2sinθ) 求化简