
数字黑色

0gavif4b8cdvgc3qtlbkuj0qrydicojw tr6y0athbatjbasxhaphtaga=海盗战

dpu8dmpyd0pkdc7xea/7na4/ta9xxa5x2a5b2a5f2a8/7a/iabkakbiigbaa=aae

过点f作fq‖ab,延长ba到m,延长dc到n,由平行线的性质得出∠aph=∠map
图片内容是:aph×DC

aph双子

fu0b(wujg~f{q80aphdc~0d.jpg

之前看到有人说想看aph和dc联动 我就试着狂草沙雕了一下 正好一人一

0可配单

21:47 硬币 收藏 请遵守弹幕礼仪w ||红茶会领全员厨w|| 主混dc和aph